(x-2)(x+2)=x^2-4

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Solution for (x-2)(x+2)=x^2-4 equation:


Simplifying
(x + -2)(x + 2) = x2 + -4

Reorder the terms:
(-2 + x)(x + 2) = x2 + -4

Reorder the terms:
(-2 + x)(2 + x) = x2 + -4

Multiply (-2 + x) * (2 + x)
(-2(2 + x) + x(2 + x)) = x2 + -4
((2 * -2 + x * -2) + x(2 + x)) = x2 + -4
((-4 + -2x) + x(2 + x)) = x2 + -4
(-4 + -2x + (2 * x + x * x)) = x2 + -4
(-4 + -2x + (2x + x2)) = x2 + -4

Combine like terms: -2x + 2x = 0
(-4 + 0 + x2) = x2 + -4
(-4 + x2) = x2 + -4

Reorder the terms:
-4 + x2 = -4 + x2

Add '4' to each side of the equation.
-4 + 4 + x2 = -4 + 4 + x2

Combine like terms: -4 + 4 = 0
0 + x2 = -4 + 4 + x2
x2 = -4 + 4 + x2

Combine like terms: -4 + 4 = 0
x2 = 0 + x2
x2 = x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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